Which of the following describes all values of n for which n^2-1\geq{0}
(A) n\geq{1}
(B) n\leq{1}
(C) 0\leq{n}\leq{1}
(D) n\leq{-1} or n\geq{1}
(E) -1\leq{n}\leq{1}]
Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question.
Source: Veritas Prep; Book 04
Chapter: Homework
Topic: Algebra
Question: 77
Question: Page 210
Edition: Third
![]()
(A) n\geq{1}
(B) n\leq{1}
(C) 0\leq{n}\leq{1}
(D) n\leq{-1} or n\geq{1}
(E) -1\leq{n}\leq{1}]
Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question.
Source: Veritas Prep; Book 04
Chapter: Homework
Topic: Algebra
Question: 77
Question: Page 210
Edition: Third
[Reveal] Spoiler:
Answer:
Equation: n^2-1\geq{0}
(n+1).(n-1)\geq{0}
The above inequality can be broken down into the following two inequalities.
(n+1) \geq{0} and (n-1)\geq{0}
(n+1) \geq{0}
n\geq{-1}
(n-1) \geq{0}
n\geq{1}
The Official Answer is D. Why am i not getting the n\leq{-1} ? What am i doing wrong above in my calculation ?
Equation: n^2-1\geq{0}
(n+1).(n-1)\geq{0}
The above inequality can be broken down into the following two inequalities.
(n+1) \geq{0} and (n-1)\geq{0}
(n+1) \geq{0}
n\geq{-1}
(n-1) \geq{0}
n\geq{1}
The Official Answer is D. Why am i not getting the n\leq{-1} ? What am i doing wrong above in my calculation ?